Twice a certain whole number subtracted from 3 times the square of the number leaves 133. Find the number

7

Step-by-step explanation:

"a certain whole number" is a number that we don't know, so pick a variable, let's use n

"Twice" means two times, so we'll use 2n for this.

"subtracted from" means the 2n will be AFTER the minus sign.

- 2n

What goes in front? "3 times the square of the number" 3n^2

Now we have 3n^2 - 2n

Lastly, we see the result is 133. So this gives us:

3n^2 - 2n = 133 To solve, subtract 133 from both sides of the equation.

3n^2 -2n - 133 = 0 Next FACTOR.

(3n + 19)(n - 7) = 0

3n+19=0 and n-7=0

n=-19/3 and n=7

Since we are looking for a whole number choose n=7

step-by-step explanation: