The given figure of a solid made up of cylinder and a cone. If the diameter of the cylinder is 12 cm , height 80 cm ,the slant height of the cone is 10 cm , find the total surface area of the solid object.

Step-by-step explanation:

Since the diameter is 12 cm, the radius will be:

r = d/2 = 12/2 = 6 cm

Now,

Surface Area of cylinder:

Surface Area of Cone:

Surface area of the object:

= SA of cone + SA of cylinder - 2πr² (Since the base area isn't included)

= 301.6 + 3242.1 - 2(3.14)(6)²

= 3543.7 - 2(3.14)(36)

= 3543.7 - 226.2

= 3317.5 cm²

Hope this helped!

the total surface area of the solid object is

Solution given:

diameter [d]=12 cm

radius [r]= cm

height of cylinder[H]=80cm

slant height [L]=10cm

Now,

Surface Area of cylinder=

=

Surface Area of Cone:

=

Surface area Base of solid=

The total surface area of the object:

=Surface Area of cylinder + Surface Area of Cone+ Surface area Base of solid

=

=

Step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

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step-by-step explanation: