Best Answer Gets Brainliest We know that a 90-degree rotation is (x, y) --> (y, -x), but what would the formula be for a point that isn't (x, y)? (e. g. (-x, y) --> (y, -x)?).

Furthermore, it turns out that rotations by 180^\circ180  

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180, degrees or -90^\circ−90  

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minus, 90, degrees follow similar patterns:

R_{(0,0),180^\circ}(\tealD{x},\purpleC{y})=(-\tealD{x},-\purpleC{y})R  

(0,0),180  

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(x,y)=(−x,−y)R, start subscript, left parenthesis, 0, comma, 0, right parenthesis, comma, 180, degrees, end subscript, left parenthesis, start color #01a995, x, end color #01a995, comma, start color #aa87ff, y, end color #aa87ff, right parenthesis, equals, left parenthesis, minus, start color #01a995, x, end color #01a995, comma, minus, start color #aa87ff, y, end color #aa87ff, right parenthesis

R_{(0,0),-90^\circ}(\tealD{x},\purpleC{y})=(\purpleC{y},-\tealD{x})R  

(0,0),−90  

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(x,y)=(y,−x)R, start subscript, left parenthesis, 0, comma, 0, right parenthesis, comma, minus, 90, degrees, end subscript, left parenthesis, start color #01a995, x, end color #01a995, comma, start color #aa87ff, y, end color #aa87ff, right parenthesis, equals, left parenthesis, start color #aa87ff, y, end color #aa87ff, comma, minus, start color #01a995, x, end color #01a995, right parenthesis

We can use these to rotate any point we want by plugging its coordinates in the appropriate equation.

Step-by-step explanation:

Step-by-step explanation:

the same "conversion process" applies.

whatever expression was in place of the old x gets a negative sign and moves into the spot of y.

and whatever expression was in place of the old y moves into the spot of x.

so, in general, we could say

the original is (f(x), g(y)).

and the 90° rotation is then

(f(x), g(y)) -> (g(y), -f(x))

add on : that means, of course, that if the old x was already a negative number, it turns via "--" into a positive number for the new y.

last but not least : we are talking here about a 90° clockwise rotation. right?

because for the counterclockwise rotation it is

(f(x), g(y)) -> (-g(y), f(x))

true

step-by-step explanation: