The perimeter of a rectangle is 64 m and its length is 3 times its width, what is the length of the Rectangle?

Length = 24m

Step-by-step explanation:

Perimeter = 2(length + width)

then:

p = 2(e+w)   eq.1

e = 3w     eq. 2

Replacing the eq. 2 in the eq. 1

64 = 2(3w+w)

64 = 2(4w)

64 = 8w

64/8 = w

w = 8

from the eq. 2

e = 3*8

e = 24

Check:

from the eq. 1

64 = 2(24+8)

64 = 2*32

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step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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