Jacob has $1.20 worth of nickels and dimes. He has twice as many nickels as dimes. Graphically solve a system of equations in order to determine the number of nickels, x, and the number of dimes, y, that Jacob has.

12 nickles

6 dimes

Step-by-step explanation:

x = number of nickles

y = number of dimes

5x + 10y = 120

x = 2y or y = 1/2x

5x + 10(1/2x) = 120

5x + 5x = 120

10x = 120

x = 12

y = 1/2x

y = 1/2(12)

y = 6

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x