Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3). -
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Give your answer in the form y = mx + b.

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

well then therefore

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

step-by-step explanation:

do you have a copy of the table?

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)