PLEASE HELP ME !
(2,7); 3x-y =5

y = 3x + 1

Step-by-step explanation:

Parallel lines have the same slope:

Given  ax + by = c  the slope is m = -a/b

3x - y = 5

x-intercept is where y = 0

3x = 5

x = 5/3

x-intercept at (5/3, 0)

y-intercept is where x=0

-y = 5

y = -5

y-intercept at (0, -5)

To graph this line just plot the two points and draw the connecting line.

If not comfortable plotting (5/3, 0) just plug in a different value for x

and find the corresponding y value...

If x=1 then  3-y=5 ..., -y = 2 ... y = -2 ...

The point (1, -2) is on the line

3x – y = 5  ..  m = -3/(-1) = 3

The parallel line will also have slope m = 3

You need equation of the line with slope 3 through (2,7)

Point slope form:  y - y1 = m(x-x1)

y - 7 = 3(x-2)

y - 7 = 3x - 6

y = 3x + 1

As above, to find x-intercept set y=0 and solve for x

To find y-intercept set x=0 and solve for y

Then just plot the two points and draw the second line

lol

step-by-step explanation: