Find of the areas of the squares PQRSto that of ABCD where PQ=9cm and AB=5cm

Area of square PQRS is 81cm^2 and of ABCD is 25cm^2

You know its a square. Which means all the sides are equal and same length. If you dont know what's a square then here is the definition:

Square is a plane figure with four equal sides and four right (90°) angles.

So now we know both of are squares, in case of the first square, PQRS, one side length is already given which is PQ=9cm. Now one side is 9cm which means all the sides are 9cm's (PQ=9cm, QR=9cm, RS=9cm,SP=9cm). So to find area just multiply them:

9cm * 9cm = 81cm^2

Now you found the area of the first square. So for the second square, ABCD, one side length is 5 cm so all the rest three sides are also 5 cm. Again, multiply them in order to find the area:

5cm * 5cm = 25cm^2

So square PQRS is 81cm^2 to that of square ABCD is 25cm^2

CAUTIONS: IT IS NOT THAT HARD YA KNOW

By the way, hope it helps! ^^

-4

step-by-step explanation:

(-4+8)=-(4-8)=-8+4=-4