HELP PLS!!

C= -3

5c + 4c + 1c=

-30

Step-by-step explanation:

We are going to substitute c as -3 in all the places it is shown:

(x is just a variable I used to represent the answer)

5c + 4c + 1c = x

5(-3) + 4(-3) + 1(-3) = x

(-15) + (-12) + (-3) = x

-30 = x

The answer is -30

Solution

If C=-3

5×-3+4×-3+1×-3

= -30

I think it will help you.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.