Eddie and Christopher went to a carnival where the games took tickets, Eddie played 9 games of ring toss and 5 games of dropping the cans, using a total of 29 tickets. At the same time,
Christopher played 3 games of ring toss and 1 game of dropping the cans, using 7 tickets.
Part A: Write a system of equation to model this situation.
Let x =
Let y =
9x + 5y = 29
3x + 1y = 7
Part B:
How many tickets does each game require.

x = 1

y = 4

Step-by-step explanation:

9x + 5y = 29 eqn 1

3x + y = 7 eqn 2

Using the method of substitution,

"substituting y"

multiplying through eqn 2 by -5

-15x - 5y = -35 eqn 2

9x + 5y =29 eqn 1

adding eqn 1 and eqn 2

-6x = -6

x = 1

3x + y = 7

3 (1) + y = 7

3 + y = 7

y = 7 - 3

y = 4

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

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