There are 3 white balls, 7 red balls, and 5 green balls in a container. A ball is chosen at random. What is the probability of choosing a green ball , keeping it, and then choosing a red ball?

(p green) 1/3

(p red) = 1/2

Step-by-step explanation:

Add the number of balls together to get the total.

3 + 7 + 5 = 15

Find the probability of choosing green.

(p green) = 5/15

reduce by 5

(p green) 1/3

Since you kept the green ball, there are now a total of 14 balls.

Find the probability of choosing red.

(p red) = 7/14

reduce by 7

(p red) = 1/2

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.