1. Determine the 10th and 21st terms of each of the following arithmetic sequences a) 7;10;13;.

b) 2;;-3;...

c) 4+7x ; 5+9x + 6+11x ;.

d) a= -2 ; Term(5)=18

e) a=5; Term(4)=4

a. 34, 67.

b. -20 1/2, -48

Step-by-step explanation:

a. the sequence is 7, 10, 13. Meaning that 3 is added to 7 to get 10, and 3 is added to 10 to get 13.

Let's find the 10th and 21st terms by adding 3:

7, 10, 13 + 3, 16 + 3, 19 + 3, 22 + 3, 25 + 3, 28 + 3, 31 + 3, 34 + 3, 37 + 3, 40 + 3, 43 + 3, 46 + 3, 49 + 3, 52 + 3, 55 + 3, 58 + 3, 61 + 3, 64 + 3, 67 + 3.

34, and 67, the 2 bolded numbers represent the 10th and 21st terms.

b. the sequence is 2, -1/2, -3. Meaning that -2 1/2 is subtracted from 2 to get to -1/2, and subtracted -2 1/2 from -1/2 to get to -3.

Let's find the 10th and 21st terms by subtracting -2 1/2:

2, -1/2, -3 -2 1/2, -5 1/2 - 2 1/2, -8 - 2 1/2, -10 1/2 - 2 1/2, -13 - 2 1/2, -15 1/2 - 2 1/2, -18 - 2 1/2, -20 1/2 - 2 1/2, -23 - 2 1/2, -25 1/2 - 2 1/2, -28 - 2 1/2, -30 1/2 - 2 1/2, -33 - 2 1/2, -35 1/2 - 2 1/2, -38 - 2 1/2, -40 1/2 - 2 1/2, -43 - 2 1/2, -45 1/2 - 2 1/2, -48.

-20 1/2, and -48 the 2 bolded numbers represent the 10th and 21st terms.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

two? xd

step-by-step explanation: