Hey! can someone give me the y=mx + b for: goes through the points (6, 2) and (5, 4)
lmk if you need better clarification!

y=-2x+14

Step-by-step explanation:

use point slope

y-y1=m(x-x1)

and m= y2-y1

x2-x1

m= 4-2

5-6

m=2/-1

then use the 1st formula to plug everything in

y-2=-2(x-6)

then distribute the 2 on the right side

y-2=-2x-2×-6

-2×-6 is 12 since a negative times a negative is positive

y-2=-2x+12

then to get y alone we have to get everything on the right side of the = sign, so the opposite of subtraction is addition, lets add 2 to the right

y-2=-2x+12

+2. +2

y=-2x+14

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.