Is the relation shown below a function? Use the graph below to justify your answer. (0, 3), (1, 4), (2, 3), (3, 0), (5, 4)

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

is there a question here?

step-by-step explanation: