If 1+ cos2a = 3 sin a cos a，cos a=/0 ，find tan a

1−cos2A=43

⟹cos2A=1−43

⟹cos2A=44−3

⟹cos2A=41

⟹sec2A=4

⟹secA=±2

sorry if wrong

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1