mika paid $68 for 14 movie tickets. some of the tickets were adult tickets, and some were student tickets. each adult ticket cost $6 and each student ticket cost $4. how many adult tickets and how many student tickets did she buy

8 student tickets and 6 adult tickets

Step-by-step explanation:

We know Mika paid $68, and we know he bought 14 movie tickets.

We also know the cost for both adult and student tickets. To find how many of each he bought, we can write the following equation:

6a + 4s = 68

(a means amount of adult tickets and s means amount of student tickets)

Since we don't know the amount of either adult or student tickets, we can guess the values and plug them into the equation.

Let's try 10 student tickets and 4 adult tickets

6(4) + 4(10) = 64

Okay, the total value isn't 64, but it's close. Let's try something close to that.

Let's try 8 student tickets and 6 adult tickets

6(6) + 4(8) = 68

We used guessing and a bit of logic to get the answer

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100