Please I need help with this question

a=6cm b=8cm h=4Cm

we have a+b/2×h

=8+6/2×4

14\2×4

7×4

28

Now, a of triangle = 1\2 bh

1\2×5cm×4Cm

10

then a of trapezoid = a1+a2

=28+10=38# Answer

$9.41

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204