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Step-by-step explanation:

Let the breadth of the rectangle be x cm.

Then the length of the rectangle will

be (x+4)cm .

Therefore, the area of the given rectangle = length × breadth

=(x+4) x (x^ 2 +4x)cm^ 2

By the given condition, we have: Area of the new rectangle le = Area of the given rectangle e + 81 cm ^ 2

Area of the new rectangle = New length ×

New breadth

(x ^ 2 + 4x) + 81 = [(x + 4) + 3](x + 3)

x ^ 2 + 4x + 81 = (x + 7)(x + 3)

x ^ 2 + 4x + 81 = x(x + 3) + 7(x + 3)

x ^ 2 + 4x + 81 = x ^ 2 + 3x + 7x + 21

x ^ 2 + 4x + 81 = x ^ 2 + 10x + 21

4x + 81 = 10x + 21 (Cancelling x² in both sides)

4x - 10x = 21 - 81 (Transposing 10x and 81)

- 6x = - 60

(- 6x)/- 6 = - 60/- 6

(Dividing both sides by -6).

x = 10

Thus,

The breadth of the rectangle is 10 cm

and

The length of the rectangle is 10 + 4 = 14 cm

Check:

(1) (14-10)cm=4cm , i.e. the length of rectangle exceeds the breadth by 4cm .

(2) New ength = 10 + 7 = 17 cm and new breadth =10+3=13 cm .

Therefore, area of the new rectangle - area of the given rectangle

= 17 × 13 - 14 × 10

= 221-1

= 81 cm .

1010: 3030

is it i think

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