The cost of 10 balls is rupees 36 , Find the cost of 48 balls using ( the method ) 1. unitary method
2. Direct variation method

only answer if you know the answer
the sum must be done in both methods

Answer :-

Step by step explanation :-

Cost of 10 balls = 36

Cost of one ball = 36 / 10 => 3.6

Cost of 48 balls = 48 × 3.6

=> 172.80

No. of balls (a)

10

48

Cost of balls ( b)

36

y

Direct Variation ( a / b )

Cost of 48 balls is 172.80 rupees

Hope it helps~

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.