Drag each system of equations to the correct location on the table. Classify each system of equations as having a single solution, no solution, or infinite solutions. Y = 5 − 2x 4x 2y = 10 x = 26 − 3y 2x 6y = 22 5x 4y = 6 10x − 2y = 7 x 2y = 3 4x 8y = 15 3x 4y = 17 -6x = 10y − 39 x 5y = 24 5x = 12 − y.

25% is the answer

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)