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Mathematics, 23.01.2022 02:40 rainbowsadie7140

From one settlement to another 4 km away, John walked 1 km / h faster than going back. So on the way back, it took 12 minutes longer. Solving which equation would we know at what speed John was going if we denoted that speed x km / h? A. 4x βˆ’ 1βˆ’4x = 15

B. 4x βˆ’ 1βˆ’4x = 12

C. 4x + 1-4x = 15

D. 4x βˆ’ 4x βˆ’ 1 = 12

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