Given triangle JKL is congruent to triangle PQR. Find x and RP

x=
RP=

RP=15

x=14

Step-by-step explanation:

ΔJKL≅ΔPQR so JK=PQ, KL=QR, and JL=PR.

KL=3y-2 and QR=22

So, 3y-2=22 and 3y=24 and y=8

Now, that we know y=8 we can plug it in 2y-1 to find RP

2(8)-1=16-1=15

In congruent triangles, the corresponding angles are also congruent.

So, ∠K≅∠Q

∠K=42 and ∠Q=3x

So, 42=3x and x=14

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