Can someone help me with the attached challenging slope problem?

Triangles A and E could lie on a graphed lin with a slope of 6

Triangles B and F could lie ona graphed line with a slope of 1/4

Triangles C and D could lie on a graphed line with a slope of 2/5

Step-by-step explanation:

The slope is rise over run.

Triangle A goes up 54 and to the right 9 so the slope is 54/9=6

Triangle B goes up 15 and to the right 60 so the slope is 15/60=1/4

Triangle C goes up 18 and to the right 45 so the slope is 18/45=2/5

Triangle D goes up 16 and to the right 40 so the slope is 16/40=2/5

Triangle E goes up 72 and to the right 12 so the slope is 72/12=6

Triangle F goes up 13 and to the right 52, so the slope is 13/52=1/4

From there we can find which slopes are the same.

180°

step-by-step explanation:

sum of equilateral triangle=180°

< n=60°

< m=120°°[angle supplementary of equilateral angle]

< m+< r+< x=360°(sum of exterior angle of triangle)