Step-by-step explanation:
a). x-5 = -4
βx = -5+5
Therefore, x = 0 = 1
b). -8x - 2 = -8
β-8x = -8-2
β-8x = -10
βx = -10Γ·-8
βx = 10/8
Therefore, x = 5/4
c). 3x + 26 = 5x
β3x -5x = -26
β-2x = -26
βx = -26Γ·-2
βx = -26/-3
Therefore, x = 26/3
d). 12 = 4(-17+ 5x)
β12 = -68 + 20x
β12 +68 = 20x
β80 = 20x
βx = 20/80
Therefore, x = 1/4
e). x = (3/4)x -2
β x -(3/4)x = -2
Therefore, x = 6
f). 0.5x + 4.75 = 13
β0.5x = 13-4.75
β0.5x = 8.25
βx = 8.25/0.5
Therefore, x = 16.5
g). 127.5 = 12x+(60/8)
β127.5 = 12x + (30/4)
β-12x = (30/4) - 127.5
β-12x = (30/4) - (127.5/1)
β-12x = (30*1 - 127.5*4)/4
β-12x = (30- 510)/4
β-12x = -480/4
β-12x = -240/2
β-12x = -120
βx = -120/-12
Therefore, x = 10
h). (1/7)(-20-4x)=-4
β(-20-4x)/7 = -4/1
β1(20-4x) =7 (-4)
β20 - 4x = -28
β-4x = -28-20
β-4x = -8
βx = -8/-4
Therefore, x = 2
i). -18 = x - 12
β-18 + 12 = x
β-6 = x
Therefore, x = -6
j). -7(2/3) = 4x-9
β-(21+2)/3 = 4x - 9
β-(23/3) = 4x -9
β-(23/3) + 9 = 4x
β-(23/3) + (9/1) = 4x
β-(23*1 + 9*3)/3 = 4x
β(-23 + 27)/3
β(4/3) = 4x
β(4/3)Γ·4 = x
β(4/3) Γ (1/4) = x
β(4*1)/(3*4) = x
β4/12 = x
Therefore, x = 4/12
l). -6(2.5x + 8) = -123
β-15x -48 = -123
β-15x = -123+ 48
β-15x = -75
βx = -75/-15
Therefore, x = 5
m). -19x = 100 + x
β-19x - x = 100
β-20x = 100
βx = 100/-20
Therefore, x = -5
n). 0.2x - 0.5 = 1.2
β0.2x = 1.2 + 0.5
β0.2x = 1.8
βx = 1.8/0.2
Therefore, x = 4
o). (-2)Β² - 3x = -17
β(-2*-2) - 3x = -17
β4 - 3x = -17
β-3x = -17-4
β-3x = -21
βx = -21/-3
Therefore, x = 7
p). -(1/2)x -(4/5) = 19/4
β-(1/2)x = (19/4) + (4/5)
Take the LCM of the denominator 4 and 5 is 20.
β-(1/2)x = (19*5 + 5*4)/20
β-(1/2)x = (95 + 16)/20
β-(1/2)x =111/20
βx = (111/20) + (1/2)
Again take the LCM of the denominator 20 and 2 is 20.
βx = (111*1 + 1*10)/20
βx = (111 + 10)/20
βx = (121/20)
Therefore, x = 121/20
q). (x/8) + 2 = 1/4{(5/16) + 8}
β(x/8) + 2 = (5/64) + 2
β(x/8) + 2 = (5/64) + (2/1)
Take the LCM of the denominator 1 and 64 is 64 in RHS.
β(x/8) +2 = (5*1 + 2*64)/64
β(x/8) + 2 = (5 + 128)/64
β(x/8) + 2 = 133/64
βx/8 = (133/64) - 2
βx/8 = (133/64) - (2/1)
Take the LCM of the denominator 1 and 64 is 64 in RHS.
βx/8 = (133*1 - 2*64)/64
βx/8 = (133 - 128)/64
βx/8 = 5/64
On applying cross multiplication, then
βx(64) = 8(5)
β64x = 40
βx = 40/64
βx = (40Γ·4)/(64Γ·4)
βx = 10/12
βx = (10Γ·2)/(16Γ·2)
Therefore, x = 5/8
r). -6 = -3{(1/7)x + (4/14)}
β-6 = -(3/7)x -(6/7)
β-6 + (6/7) = -(3/7)x
β-(6/1) + (6/7) = -(3/7)x
Take the LCM of the denominator 1 and 7 is 7 in LHS.
β(-6*7 + 6*1)/7 = -(3/7)x
β(-42 + 6)/7 = -(3/7)x
β-(36/7) = -(3/7)x
On applying cross multiplication, then
β7(36) = 21x
β252 = 21x
β252/21= x
β12 = x
Therefore, x = 12
s). (1/4)x = 11/4
βx = (11/4) - (1/4)
βx = (11-1)/4
βx = 10/4
β(10Γ·2)/(4Γ·2)
Therefore, x = 5/2
t). x - (-3) = 9
βx + 3 = 9
βx = 9-3
Therefore, x = 6.
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