A teacher is randomly handing out tests. There are 2 different versions of the test, Test A and Test B. If there are 24 tests in all and an equal number of each version, what is the probability that the
first 4 students will all receive Test A?

15/322

Step-by-step explanation:

There are 12 tests of test A, and there are 12 tests of test B.

For the student to get A, it is a 12/24 chance.

For the next student, it is a 11/23 chance

For the next 10/22

For the next 9/21

12/24*11/23*10/22*9/21=15/322

15/322 chance

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )