Write as product
8x^3-1

(2x - 1)(4x² + 2x + 1)

Step-by-step explanation:

use difference of cubes formula:  x³ - y³ = (x - y)(x² + xy +y²)

  8x³ - 1 = (2x)³ - 1³  ⇒  x = 2x  and  y = 1

  (x - y)(x² + xy +y²)

= (2x - 1)((2x)² + 2(1)x + 1²)

= (2x - 1)(4x² + 2x + 1)

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

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