Find the real zeros for:
F(x)=x^5-x^2+6

x=-1.334

Step-by-step explanation:

Let first use descrates rule of signs to find possible zeroes.

First, find the number of signs changes to find possible positive zeroes.

Here,

we have

We have 2 signs changes so we have either

2 positive zeroes, or none.

To find. negative subsitue -x for x.

There is one sign change so we have 1 negative zzeroes.

The fundamental theorem algebra tells us that for a function which a leading degree n has exactly n roots at most.

The leading degree has 5 roots so we have either

2 positive zeroes 1 positive zero, or 2 complex zeroes.

or

4 complex zeroes, 1 positive zero.

So let see first.

Rational Roots Theroem isn't applicable, because we have no zeroes. that are rational.

We must use a table of values to find a zero.

If you plug in -2 and -1, the sings oscillate so we have a zero between

-2 and-1.

So using the Theorem, the zero has to between -30 and 4.

In fact, if we plug the function in a graphing calculator, we get this.

So we have one real zero x=-1.334

i think that you should ask google for the answer to that problem because if we don't know it google does

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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