The length of a rectangle is 5cm longer than its width. If the perimeter of the rectangle is 66cm, find its length and width.

width is 14, length is 19

Step-by-step explanation:

let w represent the width of the rectangle.

"The length of a rectangle is 5 cm longer than its width."

You can take from this that you must add 5 to the width to get the length.

so, you can now write that L=w+5 .

The formula for perimeter is 2w+2L.

You can plug the values in.

2w+2(w+5) is the expression you get.

use distributive property on the 2(w+5) to get 2w+ 2w+10 . Add same terms together and get 4w+10, which represents the perimeter.

"..The perimeter of the rectangle is 66 cm."

Set the simplified expression 4w+10 to 66 to get

4w+10=66

Subtract 10 from both sides and get

4w=56

divide by four for both sides and get w=14 .

We are not done yet!

To find the length, plug the width back into our formula L=w+5 and get L=14+5. The length is 19.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0