What is the equation of the circle in General Form whose center is at ( 3, -4) and a radius of 5 units? 1. x² + y² - 6x + 8y + 50 = 0
2. x² + y² -6x + 8y - 50 = 0
3. x² + y² - 6x + 8y = 0
4. x² + y² + 6x - 8y = 0

3. x²+y²-6x+8y = 0 is the correct answer.

Step-by-step explanation:

Let the point P(x,y) be any point at locus of the circumference of the circle,

Let the center be A(3,-4).

now

AP = 5

or,

or, (x-3)²+(y+4)² = 25

or, x²-6x+9+y²+8y+16 = 25

or, x²-6x+8y+y² = 25-25

so, x²-6x+8y+y² = 0

idk sry

step-by-step explanation:

step-by-step explanation:

to find if any function is an inverse of the other, put the first equation in as x in the next one. then simplify and solve. if at the end you get the statement y = x, then it is an inverse. if you get anything else, it is not.