Two sides of a triangle are exactly the Same length. The length of the third side is four cm shorter than the two equal sides. Find the length of each side if the perimeter of the triangle is 41 cm

15 cm, 15 cm, 11 cm

Step-by-step explanation:

let the equal sides be x then the third side is x - 4

The perimeter is the sum of the 3 sides and is 41 cm , then

x + x + x - 4 = 41

3x - 4 = 41 ( add 4 to both sides )

3x = 45 ( divide both sides by 3 )

x = 15

x - 4 = 15 - 4 = 11

The sides are 15 cm, 15 cm, 11 cm

answer:  

123455421

step-by-step explanation: easy

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.