Question 5 20 pts
Scientists trying to calculate the half-life (the time it takes for half of a sample to decay)
of Phosphorus-32, took measurements of the sample once every day for five days. On
what day should about a tenth of the original amount of P-32 remain? (Round answer to
the nearest day.)
Day Mass (g)
t
0
100
1
95
2
90.5
3
85
4.
82
u
78
?
10

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

the answer is 1/4

step-by-step explanation:

b. ol

step-by-step explanation:

i got the answer right on edg.

congruent: (geometry) (of figures) identical in form; coinciding exactly when superimposed.