A newspaper carrier has $4.40 in change. He has six more quarters than dimes but three times as many nickels as quarters. How many coins of each type does he have?

Let q represent the number of quarters he has. Then q-9 is the number of dimes, and 3q is the number of nickels. His total change is ...

0.25q + 0.10(q-9) + 0.05(3q) = 7.10

0.50q - 0.90 = 7.10

q = (7.10 +0.90)/0.50 = 16

The carrier has 16 quarters, 7 dimes, and 48 nickels.

Step-by-step explanation:

Step-by-step explanation:

Given:

Equations:

Solve by substitution:

Find n and q:

the statemwnt is the company makes small and large snow cone cups.

large=it holds more then the small

small=it holds less then the large

coin flip

non-answer:

choosing

sorry if this isnt what you're looking for i dont really understand the question