Write the equation of the line passing through the points (0, 0), (2, 1), and (−2, −1). PLEASE HELP

Equation of a line:

y = mx +b

Where;

m = slope

b = y-intercept

You are given the y-intercept from the point (0,2). When x = 0, y = 2

You can then see from the Eq: y = mx + b  

that b = 2

The slope, m is found by calculating the change in y over the change in x or "rise over run".

m = (y1-y2)/(x1-x2)

One of the points is (x1, y1) and the other (x2, y2)

m = (2-(-1)) / (0 -(-1)) = (2+1)/(0+1) = 3/1 = 3

So the Eq. for the line passing through the two points is;

y = 3x + 2

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Richard C. answered • 09/06/16

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Melissa,

Let's start with the point-slope form:

(y - y1) = m(x - x1) where m is the slope.

First, find the slope m:

m = (y2 - y1)/(x2 - x1)

m = (-1 - 2)/(-1 - 0)

m = -3/-1

m = 3

Now, using either coordinate (I'll use the first), the equation looks like this:

(y - 2) = 3(x - 0)

y - 2 = 3x

Add 2 to both sides:

y = 3x + 2 (the equation of the line in slope-intercept form where y = 2 is the y-intercept.

Step-by-step explanation:

it would be 6xy and -16xy.