Find the 29th term 29,33,37,41
(arithmetic)

a₂₉ = 141

Step-by-step explanation:

The nth term of an arithmetic sequence is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 29 and d = a₂ - a₁ = 33 - 29 = 4 , then

a₂₉ = 29 + (28 × 4) = 29 + 112 = 141

The 29th term of arithmetic sequence is 141.

Step-by-step explanation:

Here's the required formula to find the arithmetic sequence :

Substituting all the given values in the formula to find the 29th term of arithmetic sequence :

Hence, the 29th term of arithmetic sequence is 141.

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation: