Find the value of x plsss the people that answerd this got it wrong.

155°

Step-by-step explanation:

The total of the angles in a triangle is 180° and also any pair or trio of angles that maje a straight angle also add up to 180°. So look for those set ups.

The left most triangle has an angle marked 35° and also a right angle is labelled. The right angle is 90° So the third angle must be 180° - (35°+90°)

180° - 125°

55°

The 55° angle(we just found) and the 60° angle (labelled) and a third unmarked angle all together maje a straight angle, 180°.

So we can calculate the third angle, which is an angle in the other shown triangle.

180° - (55° + 60°)

180° - 115°

65°

This triangle also has a right angle in it. And the third angle can be calculated in the same way.

180° - (65° + 90°)

180° - 155°

25°

Last time, the 25° angle and the angle marked x make a straight angle.

180° - 25°

155°

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)