Two printers can complete a job in 2 hours. The faster printer can do the job, operating alone, in 4 hours. How long would it take the slower printer, operating alone, to do the job?

Let x equal the amount of time required for the second press to complete the job on its own.

The second press then operates at a rate of 1/x of the job per hour.

The two presses work together at a rate of 1/2 of the job per hour.

And the first press operates at a rate of one-sixth of the job per hour.

As a result, our equation to solve is:

1/6+1/x=1/2 multiply each term by 6x x+6=3x subtract x from each side x-x+6=3x-x group like terms together

2x=6 multiply both sides by 2 x=3 the number of hours required for the second press to finish the job

CK

1/6+1/3=1/2

1/6+2/6=1/2\s3/6=1/2

1/2=1/2\salso\s(1/6)*2=1/3\s(1/3)*2=2/3\s2/3+1/3=1 (Only one job)

1=1