The lengths of a lawn mower part are approximately normally distributed with a given mean Mu = 4 in. And standard deviation Sigma = 0. 2 in. What percentage of the parts will have lengths between 3. 8 in. And 4. 2 in. ? 34% 68% 95% 99. 7%.

78.59 is the mean

step-by-step explanation:

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation:

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x