You are given a triangle with side lengths of 3, 7 and x. Use this to answer the following questions. Be sure all answers are exact and in simplest radical form where appropriate. (When the problems refer to the "longest side", there may be another side of the triangle equal to the longest side but not greater.)
a) Write an inequality to represent all possible values for x that will make a triangle. (1 pt)
b) Find the value of x that makes the triangle right when the longest side is 7. (1 pt)
c) Find the value of x that makes the triangle right when x is the longest side of the triangle. (1pt)
d) Find the value(s) of x that will make the triangle acute when the longest side is 7. (1 pt)
e) Find the value(s) of x that will make the triangle acute when the longest side is x. (1 pt)
f) Find the value(s) of x that will make the triangle obtuse when the longest side is 7. (1 pt)
g) Find the value(s) of x that will make the triangle obtuse when the longest side is x. (1 pt)
Describe all values of x that make the triangle right, acute and obtuse with sides of 3, 7 and x. (3 pts)

im not quite sure if this is right but i got 5.6 oisutuve

step-by-step explanation:

sadsdda

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!