1.The table provides various values, including all minimums and maximums, of a cosine function f (x) on the interval [0, 2π]. Angle 0 pi over 6 pi over 2 5 pi over 6 3 times pi over 2 2π
f (x) 1 0 –1 0 3 1
What is the period of the function?
A) 2 times pi over 3
B) pi over 2
C) π
D) 2π

2.On a dogleg golf hole, one golfer hits the ball 270 yards and then another 170 yards to reach the green. The angle between the two hits is equal to 100 degrees. How far would the golfer have to originally hit the ball for it to go directly to the same position on the green?
A) 150.463 yards
B) 106.746 yards
C) 343.134 yards
D) 117,740.903 yards

3. A sine function has an amplitude of 2, a period of π, and a phase shift of negative pi over 4 period What is the y-intercept of the function?
A) 2
B) 0
C)–2
D) pi over 4

Problem 1

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Explanation:

The given table we have is

If you were to graph all those points and draw a cosine curve through them, then the function you should get is

The B coefficient is 1, so that leads to a period of

T = 2pi/B

T = 2pi/1

T = 2pi

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Problem 2

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Explanation:

Draw out a triangle with these properties

We'll use the law of cosines to find side c

c^2 = a^2 + b^2 - 2*a*b*cos(C)

c^2 = 270^2 + 170^2 - 2*270*170*cos(100)

c^2 = 117740.902710

c = sqrt(117740.902710)

c = 343.133943

c = 343.134

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Problem 3

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Explanation:

If you started with y = sin(x) and applied the transformations stated, then you should end up with

From here, plug in x = 0 to find the y intercept.

a reflection across the x-axis , followed by the by a reflection across the y-axis , and then a scale dilation of 0.5 .

.19875994384

step-by-step explanation:

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