If two fair dice are rolled, what is the probability that the total showing is either even or less than nine?

1/2 and 13/18 respectively

Step-by-step explanation:

even-number results:

2, 4 6 ,8, 10 and 12

the combinations of each result are respectively

1+3+5+5+3+1 = 18

The total number of combinations on a roll pair is 36

then the probability of obtaining an even result is:

p = 18/36 = 1/2 or 0.5

so that the result is less than nine, we eliminate the combinations of results 9, 10, 11 and 12:

4 + 3 + 2 + 1 = 10

36 -10 = 26

the probability of obtaining a result less than nine is:

p = 26/36 = 13/18 or 0.72

Hope this helps

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step-by-step explanation:

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof