Find the zeros of the following function. State the multiplicity of multiple zeros. y=(x+1) 2(x-1)(x-2)

Zeros: -1, 1, 2

Step-by-step explanation:

Hi there!

The zero-product property states that if two terms, when multiplied, equals 0, one of the terms must be equal to 0.

Therefore, we know that either (x+1), (x-1) or (x-2) is equal to 0:

x+1 = 0

x-1 = 0

x-2 = 0

Now, to solve for the zeros of the function, we can just solve for x:

x+1 = 0 ⇒ x = -1

x-1 = 0 ⇒ x = 1

x-2 = 0 ⇒ x = 2

Notice how for the function, (x+1) is raised to a power of 2. This means that the zero -1 has a multiplicity of 2.

The other zeroes, 1 and 2, have multiplicities of 1.

I hope this helps!

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

answer

step-by-step explanation: