Please solve the following.

Step-by-step explanation:

The usual rules at an intersection of lines apply:

In addition, where a transversal crosses parallel lines, ...

This means, in effect, for this geometry where parallel lines cross parallel lines, all acute angles have the same measure, all obtuse angles have the same measure, and the obtuse angles are supplementary to the acute angles.

  x° = 180° -106° = 74° . . . . . . x and 106 are supplementary

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  2y° = x° . . . . . . . . . . . . . . x and 2y are corresponding

  y = 74/2 = 37 . . . substitute for x, divide by 2

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  (4z +6)° = 106° . . . . . . obtuse angles are congruent

  4z = 100 . . . subtract 6

  z = 100/4 = 25

The variable values are ...

All obtuse angles are 106°; all acute angles are 74°.

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

idn

step-by-step explanation: