Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested.
If 1.4% of the thermometers are rejected because they have readings that are too high and another 1.4% are
rejected because they have readings that are too low, find the two readings that are cutoff values separating
the rejected thermometers from the others.
Please round answers to 3 decimal places.
interval of acceptable thermometer readings =
C

Use z = (x - μ)/σ or  x = zσ + μ

Given: μ = 0 oC, σ = 1.00 oC

94% = .9400 on a z-table falls half-way between z = 1.55 and z = 1.56 --> z = 1.555

x = 1.555(1.00 oC) + 0 oC = 1.555 oC

P94 = 1.555 oC

Step-by-step explanation:

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

mk./km: lm

step-by-step explanation:

,mlmlm

; mk

lk