I need to know how to solve this algebra problem

8(x2+2x-8)
8(x2+4x-2x-8)
8[(x2+4x]-(2x-8)]
8[x(x+4)-2(x+4)]

8(x-2)(x+4) is your final answer

Wait can you check if this is right: 8(x^2 + 2x - 8)
if that’s correct, this is the explanation:
first look at all of your terms: 8x^2, 16x, and 64.
find the greatest common factor which is 8 (because all of them have a factor of 8)
factor the 8 out of all of the terms and put an 8 outside of the parenthesis.
you will end up with 8(x^2 + 2x - 8)