Consider the system of equations y + 2kz = 0 x + 2y + 6z = 2 kx + 2z = 1 where k is an arbitrary constant. (a) For which values of the constant k does this system have a unique solution? (b) For which values of the constant k does this system have no solution?

answer: it's a

step-by-step explanation:

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3