the lines whose equations are 7x-3y=1 and 6x+y=8 intersect at one point. What is the x-coordnate at that point

  x = 1

Step-by-step explanation:

Using the second equation to substitute for y in the first equation will eliminate the y-variable and give you an equation for the x-coordinate.

  y = 8 -6x . . . . second equation solved for y

  7x -3(8 -6x) = 1 . . . . substituted into the first equation

  7x -24 +18x = 1 . . . . eliminate parentheses

  25x = 25 . . . . . . . . add 24

  x = 1 . . . . . . . . . . . . divide by the coefficient of x

The x-coordinate of the point of intersection is 1.

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Additional comment

The y-coordinate can be found using our equation for y:

  y = 8 -6(1)

  y = 2

step-by-step explanation:

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see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2