-3,2 and 8,2 in slope intercept form

y = 2

Step-by-step explanation:

So we need to find the slope first.

m = y_2 - y_1/x_2 - x_1

Substitute

m = 2 - (2)/8 - (-3)

Simplify now.

Multiply -1 by 2

m = 2 - 2/(8 - (-3)

2 from 2

m = 0/8 - (-3)

Now we need to simplify the denominator.

To do so lets multiply -1 by -3

m = 0/8 + 3

m = 0/11

m = 0

Now we have the slope of 0 and the given point of (-3, 2)

So y - (2) = 0 * (x - (-3)) (Formula > y - y_1 = m(x - x_1) this comes from the original slope equation]

Simplify further

y - 2 = 0 * (x + 3)

Now we solve for y

Multiply 0 by x + 3

y - 2 = 0

Add 2 to both sides

y = 2

-3,2 and 8,2

Step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}