What should be in each box

3/7 in box 3

2/7 in box 1

42 in box 2

The first box (y+4/7=6/7) should have 2/7

---Subtract 4/7 from both sides to get y alone. y=2/7

The second box (17+b=60) should have 43

---Subtract 17 from both sides to get b alone. b=43

The third box (6/7=m+3/7) should have 3/7

---Subtract 3/7 from both sides to get m alone. m=3/7

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

c.)

step-by-step explanation: