I need help on number 10 and 9

1. 55 ft   2. 10 ft. 3.3 in.

Step-by-step explanation:

For question 9, you need to understand that the angle on the left is equal to the one on the right from the mirror priniciple. Now let's say the height of the dinosaur is x ft. We would get the equation 5.5/4 = x/40 and we get that x is 55, thus the height of the dinosaur is 55 ft

For question 10, we use the same similarity principle as we use in question 9 so given that the height of the light pole is h in. we get the equation

h/185 = 62/93

So, h is 123.33(I used a calculator, hope that's fine). Thus the height of the light pole would be 123.33 in. or 10 ft. 3.3 in.

Hope this helps

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.