![\begin{cases} -x+3y=9\\\\ y=\cfrac{2}{3}x \end{cases} \\\\[-0.35em] ~\dotfill\\\\ -x+3y=9\implies 3y=9+x\implies \underline{3y-9=x} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting ont the 2nd equation}}{y=\cfrac{2}{3}(\underline{3y-9})\implies 3y=2(3y-9)}\implies 3y=6y-18\implies 18+3y=6y \\\\\\ 18=3y\implies \cfrac{18}{3}=y\implies \boxed{6=y}](/tpl/images/2657/8656/7c6e6.png)
PLease hurry! i need it! And the testing thing is happening, so before 6 pm?
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Mathematics, 13.02.2022 06:00 kcarstensen59070
PLease hurry! i need it! And the testing thing is happening, so before 6 pm?
Answers: 1
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